(30x^2)+30x-180=0

Solution for (30x^2)+30x-180=0 equation:

(30x^2)+30x-180=0

a = 30; b = 30; c = -180;
Δ = b2-4ac
Δ = 302-4·30·(-180)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-150}{2*30}=\frac{-180}{60}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+150}{2*30}=\frac{120}{60}
=2
$